Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:
7 men, 5 women and 8 children were given an assignment of distributing 2000 books to students in a school over a period of three days. All of them distributed books on the first day. On the second day, 1 man, 3 women and 3 children remained absent and on the third day, 4 men and 5 children remained absent. If the ratio of the number of books distributed in a day by a man, a woman and a child was 5 : 4 : 2 respectively, a total of how many books were distributed on the second day?
Answer
Answer (as printed):
Explanation
Let the number of books distributed in a day by a man, a woman and a child be $5x, 4x$ and $2x$ respectively. Then, number of books distributed on the first day $=(7\times 5x+5\times 4x+8\times 2x)=71x$. Number of books distributed on the second day $=(6\times 5x+2\times 4x+5\times 2x)=48x$. Number of books distributed on the third day $=(3\times 5x+5\times 4x+3\times 2x)=41x$. $$\therefore \quad 71x+48x+41x=2000 \Rightarrow 160x=2000 \Rightarrow x=\frac{2000}{160}=\frac{25}{2}.$$ Hence, number of books distributed on the second day $=48x=\left(48\times\frac{25}{2}\right)=600$.
Explanation as extracted from the printed page; notation may be imperfect.