Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:
If $a+b: b+c: c+a=6: 7: 8$ and $a+b+c=14$, then the value of $c$ is
(a)6
(b)7
(c)8
(d)14
Answer
Answer (as printed): A
Explanation
Let $a+b=6 k, b+c=7 k$ and $c+a=8 k$. Adding, we get : $2(a+b+c)=21 k \Rightarrow 2 \times 14=21 k$ $$\Rightarrow k=\frac{28}{21}=\frac{4}{3} .$$ So, $a+b=6 k=6 \times \frac{4}{3}=8$. $$\therefore c=(a+b+c)-(a+b)=14-8=6 .$$
Explanation as extracted from the printed page; notation may be imperfect.