Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:
Six numbers $a, b, c, d, e, f$ are such that $a b=1, b c=$ $\frac{1}{2}, c d=6, d e=2$ and $e f=\frac{1}{2}$. What is the value of (ad : be : cf)?
(a)4 : 3 : 27
(b)6 : 1 : 9
(c)8 : 9 : 9
(d)72 : 1 : 9
Answer
Answer (as printed): D
Explanation
$a d=\frac{a b \times c d}{b c}=\frac{1 \times 6}{(1 / 2)}=12$. $b e=\frac{b c \times d e}{c d}=\frac{\frac{1}{2} \times 2}{6}=\frac{1}{6}$. $c f=\frac{c d \times e f}{d e}=\frac{6 \times \frac{1}{2}}{2}=\frac{3}{2}$. $\therefore a d: b e: c f=12: \frac{1}{6}: \frac{3}{2}=72: 1: 9$.
Explanation as extracted from the printed page; notation may be imperfect.