Subject: General Aptitude · Chapter: Ratio and Proportion · Exam: · Marks: · Difficulty:
What is the value of $x+y : x-y$? I. $x:y = 1:2$ II. $x = \frac{y}{2}$ and $y-x=3$
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.
Explanation
I. $\frac{x+y}{x-y}=\frac{\frac{x}{y}+1}{\frac{x}{y}-1}=\frac{\frac{1}{2}+1}{\frac{1}{2}-1}=\frac{3}{2}\times(-2)=-3$. II. $x=\frac{y}{2}$ and $y-x=3 \Rightarrow y-\frac{y}{2}=3 \Rightarrow \frac{y}{2}=3 \Rightarrow y=6$. So, $x=\frac{y}{2}=\frac{6}{2}=3$. $\therefore \frac{x+y}{x-y}=\frac{3+6}{3-6}=\frac{9}{(-3)}=-3$.
Explanation as extracted from the printed page; notation may be imperfect.