Subject: General Aptitude · Chapter: Time and Work · Exam: 2006 · Marks: · Difficulty:
A can do a piece of work in 90 days, B in 40 days and C in 12 days. They work for a day each in turn i.e., first day A does it alone, B does it the second day and C the third day. After that A does it for another day, and so on. After finishing the work they get ` 240. If the wages are divided in proportion to the work done by them, find what each will get.
(a)A ` 24, B ` 54 and C ` 162
(b)A ` 22, B ` 50 and C ` 132
(c)A ` 26, B ` 52 and C ` 142
(d)A ` 20, B ` 44 and C ` 182 QUANTITATIVE APTITUDE
Answer
Answer (as printed): A
Explanation
(A + B + C)’s 3 days’ work = + + = . 90 40 12 360 43 344 (A + B + C)’s 24 days’ work = ×8= . 360 360 344 16 4 Remaining work = 1 – = = . 360 360 90 On 25th day, it is A’s turn. 1 A’s 1 day’s work = . 90 4 1 3 1 Remaining work = – = = . 90 90 90 30 On 26th day, it is B’s turn. 1 B’s 1 day’s work = . 40 1 1 1 Remaining work = − = . 30 40 120 On 27th day, it is C’s turn. 1 work is done by C in 1 day. 12 1 1 1 work is done by C in 12 × = day. 120 120 10 1 Hence, the whole work is completed in 26 days ou 10 of which A worked for 9 days, B worked for 9 days and 1 C worked for 8 days. 10 Ratio of wages of A, B and C = Ratio of work done by A, B and C 1 1 1 1 1 9 27 = × 9 : × 9 : × 8 = : : 90 40 12 10 10 40 40 = 4 : 9 : 27. 4 A’s share = ` × 240 = ` 24; 40 9 B’s share = ` × 240 = ` 54; 40 27 C’s share = ` × 240 = ` 162. 40
Explanation as extracted from the printed page; notation may be imperfect.