Subject: General Aptitude · Chapter: Time and Work · Exam: · Marks: · Difficulty:
A, B and C can complete a piece of work in 24, 5 and 12 days respectively. Working together, they will complete the same work in [SSC-CHSL (10+2) Exam, 2015]
A’s 1 days work = 24 1 B’s 1 days work = 5 1 C’s 1 days work = 12 ∴ (A + B + C)’s 1 days work 1 1 1 = + + 24 5 12 LCM of 24, 5 and 12 2 24 – 5 – 12 2 12 – 5 – 6 3 6–5–3 2 – 5 – 1 2 × 2 × 3 × 2 × 5 = 120 5 + 24 + 10 = 120 39 13 = = 120 40 Time taken by A, B and C to complete the work, working together 40 1 = =3 days 13 13 1
Explanation as extracted from the printed page; notation may be imperfect.