ABC26GN3755 · Time and Distance

Since A and B are 5 km apart and Ram's speed is 5 km/hr, so Ram reaches B in 1 hour i.e., at 10 a.m. Thus, when Ram reaches B, Shyam has travelled from 9:45 a.m. to 10 a.m. i.e. 15 min. So, distance covered by Shyam when Ram reaches B $=\left(10\times\frac{15}{60}\right)$ km $=\frac{5}{2}$ km. Now, Ram starts travelling from B to A. So, relative speed $=(10+5)$ km/hr $=15$ km/hr. Distance between Ram and Shyam $=\left(5-\frac{5}{2}\right)$ km $=\frac{5}{2}$ km. Time taken to cover $\frac{5}{2}$ km at relative speed $=\left(\frac{5}{2}\times\frac{1}{15}\right)$ hr $=\frac{1}{6}$ hr $=10$ min. Hence, Ram and Shyam meet each other 10 minutes after 10 a.m. i.e., at 10:10 a.m.