Subject: General Aptitude · Chapter: Time and Distance · Exam: · Marks: · Difficulty:
A hare pursued by a hound is 60 of her own leaps before him. When the hare takes 4 leaps, the hound takes 3 . In one leap, the hare goes $1 \frac{3}{4}$ metres and the hound $2 \frac{3}{4}$ metres. In how many leaps will the hound overtake the hare?
(a)84
(b)188
(c)252
(d)356
Answer
Answer (as printed): C
Explanation
60 leaps of the hare $=\left(60\times1\frac{3}{4}\right)$ m $=105$ m. So, the hound should gain 105 m over the hare. When the hound travels $\left(3\times2\frac{3}{4}\right)$ m $=\frac{33}{4}$ m, the hare travels $\left(4\times1\frac{3}{4}\right)$ m $=7$ m. In 3 leaps of the hound, the hound gains $\left(\frac{33}{4}-7\right)$ m $=\frac{5}{4}$ m. $$\therefore \text{Number of leaps required} = \left(105\times\frac{4}{5}\times3\right) = 252.$$
Explanation as extracted from the printed page; notation may be imperfect.