An amount of ₹ 1,00,000 is invested in two types of shares. The first yields an interest of 9\% p.a. and the second, 11\% p.a. If the total interest at the end of one year is $9 \frac{3}{4} \%$, then the amount invested in each share was
(a)₹ 52,500; ₹ 47,500
(b)₹ 62,500; ₹ 37,500
(c)₹ 72,500; ₹ 27,500
(d)₹ 82,500; ₹ 17,500
Answer
Answer (as printed): B
Explanation
Let the sum invested at 9\% be ₹ $x$ and that invested at $11 \%$ be ₹ $(100000-x)$. Then, $\left(\frac{x \times 9 \times 1}{100}\right)+\left[\frac{(100000-x) \times 11 \times 1}{100}\right]$ $$=\left(100000 \times \frac{39}{4} \times \frac{1}{100}\right)$$ ∴ Sum invested at $9 \%=₹ 62500$. Sum invested at $11 \%=₹(100000-62500)=₹ 37500$.
Explanation as extracted from the printed page; notation may be imperfect.