A man borrowed a total sum of ₹ 24000 from two moneylenders. For one loan, he paid interest @ $7\frac{1}{2}\%$ p.a. and for the other 9% p.a. How much money did he borrow at each rate ? I. The sum of the interests after one year was ₹ 2025. II. The interest on one sum was twice that on the other.
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.
Explanation
Suppose he borrowed ₹ $x$ at $7\frac{1}{2}\%$ p.a. and ₹ $(24000-x)$ at 9% p.a. I. gives, total interest = ₹ 2025. $\therefore \left(x \times 1 \times \frac{15}{2} \times \frac{1}{100}\right)+\left\{(24000-x) \times 1 \times \frac{9}{100}\right\}=2025$. This gives $x$.
Explanation as extracted from the printed page; notation may be imperfect.