ABC26GN4139 · Compound Interest

Subject: General Aptitude · Chapter: Compound Interest · Exam: 2007 · Marks: · Difficulty:

What annual payment will discharge a debt of ₹ 7620 due in 3 years at $16 \frac{2}{3}$ \% per annum compound interest? (G.B.O., 2007)
Answer
Answer (as printed):
Explanation
(P.W. of ₹$x$ due 1 year hence) + (P.W. of ₹$x$ due 2 years hence) + (P.W. of ₹$x$ due 3 years hence) $=7620$. $$\begin{aligned} & \therefore \frac{x}{\left(1+\frac{50}{3 \times 100}\right)}+\frac{x}{\left(1+\frac{50}{3 \times 100}\right)^{2}}+\frac{x}{\left(1+\frac{50}{3 \times 100}\right)^{3}}=7620 \\ & \Leftrightarrow \frac{6 x}{7}+\frac{36 x}{49}+\frac{216 x}{343}=7620 \Leftrightarrow 294 x+252 x+216 x=7620 \times 343 \\ & \Leftrightarrow x=\left(\frac{7620 \times 343}{762}\right)=3430 . \end{aligned}$$ ∴ Amount of each instalment $=₹ 3430$.

Explanation as extracted from the printed page; notation may be imperfect.

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