Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.
Answer
Answer (as printed):
Explanation
Side of first square $=\left(\frac{40}{4}\right) \mathrm{cm}=10 \mathrm{cm}$; Side of second square $=\left(\frac{32}{4}\right) \mathrm{cm}=8 \mathrm{cm}$. Area of third square $=\left[(10)^{2}-(8)^{2}\right] \mathrm{cm}^{2}=(100-64) \mathrm{cm}^{2}=36 \mathrm{cm}^{2}$. Side of third square $=\sqrt{36} \mathrm{cm}=6 \mathrm{cm}$. ∴ Required perimeter $=(6 \times 4) \mathrm{cm}=24 \mathrm{cm}$.