The length of a rectangle R is 10% more than the side of a square S. The width of the rectangle R is 10% less… · ABC26GN4248
Subject: General Aptitude · Chapter: Area
The length of a rectangle $R$ is 10\% more than the side of a square $S$. The width of the rectangle $R$ is 10\% less than the side of the square $S$. What is the ratio of the area of $R$ to that of $S$ ?
Answer
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Explanation
Let each side of the square $S$ be $x$ units. Then, length of rectangle $R=110 \%$ of $x=\left(\frac{11 x}{10}\right)$ units. And, width of rectangle $R=90 \%$ of $x=\left(\frac{9 x}{10}\right)$ units. ∴ Ratio of areas of $R$ and $S=\left(\frac{11 x}{10} \times \frac{9 x}{10}\right): x^{2}=\frac{99 x^{2}}{100}: x^{2}=99: 100$.
Explanation as extracted from the printed page; notation may be imperfect.