Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.
Answer
Answer (as printed):
Explanation
Let x and y be the length and breadth of the rectangle respectively. Then, x – 4 = y + 3 or x – y = 7 ...(i) Area of the rectangle = xy; Area of the square = (x – 4) ( y + 3) ∴ (x – 4) ( y + 3) = xy ⇔ 3x – 4y = 12 ...(ii) Solving (i) and (ii), we get x = 16 and y = 9. ∴ Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.
Explanation as extracted from the printed page; notation may be imperfect.