ABC26GN4261 · Area
Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
Find the area of a triangle whose sides measure 15 cm, 16 cm and 17 cm. 1
Answer
Explanation
Let $a=15 \mathrm{cm}, b=16 \mathrm{cm}$ and $c=17 \mathrm{cm}$. Then, $s=\frac{1}{2}(a+b+c)=24$. $$\begin{aligned} & \therefore(s-a)=9 \mathrm{cm},(s-b)=8 \mathrm{cm} \text { and }(s-c)=7 \mathrm{cm} . \\ & \text { Area }=\sqrt{s(s-a)(s-b)(s-c)}=\sqrt{24 \times 9 \times 8 \times 7} \mathrm{cm}^{2}=24 \sqrt{21} \mathrm{cm}^{2} . \end{aligned}$$
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