The difference between two parallel sides of a trapezium is 4 cm. The perpendicular distance between them is… · ABC26GN4273
Subject: General Aptitude · Chapter: Area
The difference between two parallel sides of a trapezium is 4 cm. The perpendicular distance between them is 19 cm. If the area of the trapezium is $475 \mathrm{cm}^{2}$, find the lengths of the parallel sides.
Answer
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Explanation
Let the two parallel sides of the trapezium be $a \mathrm{cm}$ and $b \mathrm{cm}$. Then, $a-b=4$ $$\text { And, } \frac{1}{2} \times(a+b) \times 19=475 \Leftrightarrow(a+b)=\left(\frac{475 \times 2}{19}\right) \Leftrightarrow a+b=50$$ Solving (i) and (ii), we get : $a=27, b=23$. So, the two parallel sides are 27 cm and 23 cm.