ABC26GN4288 · Area
Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
A sector of 120°, cut out from a circle, has an area of $9 \frac{3}{7} s q . c m$. Find the radius of the circle.
Answer
Explanation
Let the radius of the circle be $r \mathrm{cm}$. Then, $$\frac{\pi r^{2} \theta}{360}=\frac{66}{7} \Leftrightarrow \frac{22}{7} \times r^{2} \times \frac{120}{360}=\frac{66}{7} \Leftrightarrow r^{2}=\left(\frac{66}{7} \times \frac{7}{22} \times 3\right)=9 \Leftrightarrow r=3 .$$ Hence, radius $=3 \mathrm{cm}$.
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