ABC26GN4410 · Area
Subject: General Aptitude · Chapter: Area · Exam: 2007 · Marks: · Difficulty:
The diagonal of a square is $4 \sqrt{2} \mathrm{cm}$. The diagonal of another square whose area is double that of the first square, is
(a)8 cm
(b)$8 \sqrt{2} \mathrm{cm}$
(c)$4 \sqrt{2} \mathrm{cm}$
(d)16 cm
Answer
Explanation
$d_{1}=4 \sqrt{2} \mathrm{cm} \Rightarrow$ area $=\frac{1}{2} d_{1}{ }^{2}=\frac{1}{2} \times(4 \sqrt{2})^{2}=16 \mathrm{cm}^{2}$. Area of new square $=(2 \times 16) \mathrm{cm}^{2}=32 \mathrm{cm}^{2}$. $$\therefore \quad \frac{1}{2} d_{2}^{2}=32 \Rightarrow d_{2}^{2}=64 \Rightarrow d_{2}=8 \mathrm{cm} .$$
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