Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:
Consider the following: I. The areas of the three figures are all different.
(b)The areas of all the three figures are equal.
(c)The perimeters of the three figures are equal.
(d)The perimeters of figures I and II are equal.
Answer
Answer (as printed): B
Explanation
I. Area = (9 × 4) sq. units = 36 sq. units. Perimeter $=[2(9+4)]$ units $=26$ units. II. Area $=(6 \times 6)$ sq. units $=36$ sq. units. Perimeter $=(4 \times 6)$ units $=24$ units. III. Area $=\left(\frac{1}{2} \times 8 \times 9\right)$ sq. units = 36 sq. units. Third side $=\sqrt{8^{2}+9^{2}}=\sqrt{64+81}=\sqrt{145}$ units. ∴ Perimeter $=(8+9+\sqrt{145})$ units $=(17+\sqrt{145})$ units. Hence, the area of all the three figure area equal.
Explanation as extracted from the printed page; notation may be imperfect.