ABC26GN4605 · Area

Subject: General Aptitude · Chapter: Area · Exam: · Marks: · Difficulty:

If in the given figure $O P=O Q$ $=14 \mathrm{cm}$ and $O P, P Q$ and $O Q$ are all joined by semi-circles, then the perimeter of the shaded are a is equal to ![](
(a)88 cm
(b)176 cm
(c)264 cm
(d)352 cm
Answer
Answer (as printed): A
Explanation
Perimeter of the shaded area = Sum of circumferences of semi-circles with $O P, P Q$ and $O Q$ as diameters. $$\begin{aligned} & =\pi\left(\frac{O P}{2}\right)+\pi\left(\frac{P Q}{2}\right)+\pi\left(\frac{O Q}{2}\right) \\ & =[\pi(7+7+14)] \mathrm{cm}=\left(\frac{22}{7} \times 28\right) \mathrm{cm}=88 \mathrm{cm} . \end{aligned}$$

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