ABC26GN4770 · Volume and Surface Area

Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:

If the radius of a sphere is increased by 50%, find the increase percent in volume and the increase percent in the surface area.
Answer
Answer (as printed):
Explanation
Let original radius = R. 150 3R Then, new radius = R = . 100 2 3 4 3 4  3R  9πR 3 Original volume = πR , New volume = π   = . 3 3 2 2  19 3 3  Increase % in volume =  πR × × 100 % = 237.5%.  6 4 πR 3  2  3R  Original surface area = 4πR2. New surface area = 4π  = 9πR 2 .  2   5 πR 2  Increase % in surface area =  2 × 100 % = 125%.  4 πR 

Explanation as extracted from the printed page; notation may be imperfect.

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