Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:
The dimensions of a room are 15 m, 10 m and 8 m. The volume of a bag is $2.25 \mathrm{m}^{3}$. The maximum number of bags that can be a accommodated in the room is
(a)531
(b)533
(c)535
(d)550
Answer
Answer (as printed): B
Explanation
Required number of bags = $$\frac{\text { Volume of the room }}{\text { Volume of each bag }}=\frac{15 \times 10 \times 8}{2.25}=533.333 \approx 533 .$$
Explanation as extracted from the printed page; notation may be imperfect.