ABC26GN4797 · Volume and Surface Area

Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:

If $V$ be the volume and $S$ be the surface area of a cuboid of dimensions $a, b, c$, then $\frac{1}{V}$ is equal to

(a)$\frac{S}{2}(a+b+c)$

(b)$\frac{2}{S}\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)$

(c)$\frac{2 S}{a+b+c}$

(d)2S $(a+b+c)$

Answer

Answer (as printed): B

Explanation

$V=a b c$. $$S=2(a b+b c+c a)=2 a b c\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)$$

Explanation as extracted from the printed page; notation may be imperfect.