The length of the longest rod that can be placed in a room of dimensions 10 m × 10 m × 5 m is · ABC26GN4802
Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: S.S.C. 2010
The length of the longest rod that can be placed in a room of dimensions $10 \mathrm{m} \times 10 \mathrm{m} \times 5 \mathrm{m}$ is
(a)$15 \sqrt{3}$
(b)15
(c)$10 \sqrt{2}$
(d)$5 \sqrt{3}$
Answer
Explanation
Required length $=\sqrt{(10)^{2}+(10)^{2}+(5)^{2}} \mathrm{m}=\sqrt{225} \mathrm{m}=15 \mathrm{m}$.
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