Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: · Marks: · Difficulty:
The sum of the radius of the base and the height of a solid cylinder is 37 metres. If the total surface area of the cylinder be 1628 sq. metres, its volume is
(a)$3180 \mathrm{m}^{3}$
(b)$4620 \mathrm{m}^{3}$
(c)$5240 \mathrm{m}^{3}$
(d)None of these
Answer
Answer (as printed): B
Explanation
$(h+r)=37$ and $2 \pi r(h+r)=1628 . \therefore 2 \pi r \times 37=1628$ $$\text { or } \quad r=\left(\frac{1628}{2 \times 37} \times \frac{7}{22}\right)=7 \text {. }$$ So, $r=7 \mathrm{m}$ and $h=30 \mathrm{m}$. $$\text { ∴ Volume }=\left(\frac{22}{7} \times 7 \times 7 \times 30\right) \mathrm{m}^{3}=4620 \mathrm{m}^{3} .$$