ABC26GN4921 · Volume and Surface Area
Subject: General Aptitude · Chapter: Volume and Surface Area · Exam: 2005 · Marks: · Difficulty:
Find the number of coins 1.5 cm in diameter and 0.2 cm thick, to be melted to form a right circular cylinder of height 10 cm and diameter 4.5 cm.
Answer
Explanation
Volume of one coin $=\left(\frac{22}{7} \times \frac{75}{100} \times \frac{75}{100} \times \frac{2}{10}\right) \mathrm{cm}^{3}=\frac{99}{280} \mathrm{cm}^{3}$. Volume of larger cylinder $=\left(\frac{22}{7} \times \frac{9}{4} \times \frac{9}{4} \times 10\right) \mathrm{cm}^{3}$. Number of coins $=\left(\frac{22}{7} \times \frac{9}{4} \times \frac{9}{4} \times 10 \times \frac{280}{99}\right)=450$.
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