ABC26GN5007 · Volume and Surface Area

Volume of bigger sphere $$\begin{aligned} & =\left[\frac{4}{3}\pi\times(8)^3\right]\text{cm}^3=\left(\frac{4}{3}\pi\times512\right)\text{cm}^3. \\ & \text{Volume of 1 ball}=\left[\frac{4}{3}\pi\times(2)^3\right]\text{cm}^3=\left(\frac{4}{3}\pi\times8\right)\text{cm}^3. \\ & \therefore \text{Number of balls}=\left(\frac{\frac{4}{3}\pi\times512}{\frac{4}{3}\pi\times8}\right)=\frac{512}{8}=64. \end{aligned}$$