Subject: General Aptitude · Chapter: Races and Games of Skill · Exam: 2007 · Marks: · Difficulty:
In a 100 m race for children, A runs at 1.66 m/s. If A gives B a start of 4 m and still beats him by 12 seconds, what is B’s speed?
Answer
Answer (as printed):
Explanation
Time taken by $A$ to run 100 m $=\frac{100}{1.66} \sec =\frac{100 \times 100}{166} \sec =\frac{5000}{83} \sec$. Time taken by $B$ to run 96 m $=\left(\frac{5000}{83}+12\right) \sec =\frac{(5000+996)}{83} \sec =\frac{5996}{83} \sec$. B's speed $=\left(\frac{96 \times 83}{5996}\right) \mathrm{m} / \mathrm{sec}=\left(\frac{24 \times 83}{1499}\right) \mathrm{m} / \mathrm{s}=\frac{1992}{1499} \mathrm{m} / \mathrm{s}=1.328 \mathrm{m} / \mathrm{s}=1.33 \mathrm{m} / \mathrm{s}$.