How many arrangements can be made out of the letters of the word ‘ENGINEERING’? · ABC26GN5274

The word 'ENGINEERING' contains 11 letters, namely 3E, 3N, 2G, 2I and 1R. $\therefore$ Required number of ways $=\frac{11!}{3! \times 3! \times 2! \times 2! \times 1!}=\frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{6 \times 6 \times 2 \times 2 \times 1}=(11 \times 10 \times 7 \times 6 \times 5 \times 4 \times 3)=277200 .$