ABC26GN5274 · Permutations and Combinations
Subject: General Aptitude · Chapter: Permutations and Combinations · Exam: · Marks: · Difficulty:
How many arrangements can be made out of the letters of the word ‘ENGINEERING’?
Answer
Explanation
The word 'ENGINEERING' contains 11 letters, namely 3E, 3N, 2G, 2I and 1R. $\therefore$ Required number of ways $=\frac{11!}{3! \times 3! \times 2! \times 2! \times 1!}=\frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{6 \times 6 \times 2 \times 2 \times 1}=(11 \times 10 \times 7 \times 6 \times 5 \times 4 \times 3)=277200 .$
Explanation as extracted from the printed page; notation may be imperfect.
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