Subject: General Aptitude · Chapter: Permutations and Combinations · Exam: 2009 · Marks: · Difficulty:
In how many different ways can the letters of the word ‘DESIGN’ be arranged so that the vowels are at the two ends?
Answer
Answer (as printed):
Explanation
The given word 'DESIGN' contains 4 consonants and 2 vowels. At the two ends the two vowels can be arranged in 2 ways. Remaining 4 letters can be arranged in $4!=(4 \times 3 \times 2 \times 1)=24$ ways. Total number of ways $=(24 \times 2)=48$. $\therefore$ Required number of ways $=48$.
Explanation as extracted from the printed page; notation may be imperfect.