ABC26GN5579 · Tabulation

Total number of athletes from $C$ in various years: $$\begin{aligned} & 2005 \rightarrow(4.5+3.1) \times 100=(7.6 \times 100)=760 ; \\ & 2006 \rightarrow(6.9+3.3) \times 100=10.2 \times 100=1020 ; \\ & 2007 \rightarrow(4.8+2.8) \times 100=(7.6 \times 100)=760 ; \\ & 2008 \rightarrow(6.6+4.2) \times 100=10.8 \times 100=1080 ; \\ & 2009 \rightarrow(7.9+6.3) \times 100=14.2 \times 100=1420 ; \\ & 2010 \rightarrow(10.8+6.9) \times 100=17.7 \times 100=1770 ; \end{aligned}$$ It was second highest in 2009. So, the correct answer is (e).