ABC26IN0010 · Acids and Bases

Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acid and Bases – General · Exam: CSIR-NET JUNE 2017 · Marks: 2 · Difficulty: Easy

The compound that gives a basic solution in HF is :

(a)$\mathrm{AsF_5}$

(b)$\mathrm{PF_5}$

(c)$\mathrm{BF_3}$

(d)$\mathrm{BrF}_{3}$

Answer

Answer (as printed): D

Explanation

\[ \mathrm{AsF_5 + 2HF \rightarrow [AsF_6]^{-} + [H_2F]^{+}} \]

\[ \mathrm{PF_5 + 2HF \rightarrow [PF_6]^{-} + [H_2F]^{+}} \]

\[ \mathrm{BF_3 + 2HF \rightarrow [BF_4]^{-} + [H_2F]^{+}} \]

\[ \mathrm{BrF_3 + HF \rightarrow [BrF_2]^{+} + [HF_2]^{-}} \]

$\mathrm{BrF_3}$ acts as base as it donate $\mathrm{F^{-}}$ in HF