The cations formed upon dissolving SnF4 and AuF3 in liquid BrF3 separately, respectively are

ABC26IN0015 · Acids and Bases

Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acid and Bases – General · Exam: CSIR-NET JUNE 2019 · Marks: 2 · Difficulty: Medium

The cations formed upon dissolving $\mathrm{SnF_4}$ and $\mathrm{AuF_3}$ in liquid $\mathrm{BrF_3}$ separately, respectively are

(a)$\mathrm{SnF}_{3}{ }^{+}$and $\mathrm{BrF}_{2}{ }^{+}$

(b)$\mathrm{BrF}_{2}{ }^{+}$and $\mathrm{AuF}_{2}{ }^{+}$

(c)$\mathrm{BrF}_{2}{ }^{+}$only

(d)$\mathrm{SnF}_{3}{ }^{+}$and $\mathrm{AuF}_{2}{ }^{+}$

Answer

Answer (as printed): C

Explanation

\[ \mathrm{2BrF_3 + SnF_4 \rightarrow (BrF_2)_2[SnF_6]} \]

Species formed in reaction are $\mathrm{BrF_2^{+}}$ and $[\mathrm{SnF_6}]^{2-}$

\[ \mathrm{AuF_3 + BrF_3 \rightarrow BrF_2^{+}[AuF_4]^{-}} \]

Species formed in reaction are $\mathrm{BrF_2^{+}}$ and $[\mathrm{AuF_4}]^{-}$