ABC26IN0057 · Chemical Bonding

Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Hydrogen Bonding Weak Interactions · Exam: CSIR-NET JUNE 2012 · Marks: 2 · Difficulty: Medium

The strength of $\mathrm{P}\pi$-$\mathrm{d}\pi$ bonding in E-O (E = Si, P, S and Cl) follows the order
(a)$\mathrm{Si}-\mathrm{O}>\mathrm{P}-\mathrm{O}>\mathrm{S}-\mathrm{O}>\mathrm{Cl}-\mathrm{O}$
(b)$\mathrm{P}-\mathrm{O}>\mathrm{Si}-\mathrm{O}>\mathrm{S}-\mathrm{O}>\mathrm{Cl}-\mathrm{O}$
(c)$\mathrm{S}-\mathrm{O}>\mathrm{C} 1-\mathrm{O}>\mathrm{P}-\mathrm{O}>\mathrm{Si}-\mathrm{O}$
(d)$\mathrm{Cl-O>S-O>P-O>Si-O}$
Answer
Answer (as printed): D
Explanation
Smaller the internuclear distance between two atoms, stronger will be the $\pi$ bonds. The increasing order of internuclear distance is Cl-O < S-O < P-O < Si-O Therefore strength of $p\pi$-$d\pi$ bonding is Cl-O > S-O > P-O > Si-O

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