In a specific reaction, hexachlorocyclotriphosphazene, N3P3Cl6 was reacted with a metal fluoride to obtain mixed halo derivatives namely N3P3Cl3F (A), N3P3Cl4F (B), N3P3Cl3F3 (C), N3P3Cl2F4 (D), N3P3ClF5 (E). Compositions among these which can give isomeric products are

ABC26IN0190 · Main Group Elements

Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Exam: CSIR-NET 2013 · Marks: 2 · Difficulty: Medium

In a specific reaction, hexachlorocyclotriphosphazene, $\mathrm{N_3P_3Cl_6}$ was reacted with a metal fluoride to obtain mixed halo derivatives namely $\mathrm{N_3P_3Cl_3F}$ (A), $\mathrm{N_3P_3Cl_4F}$ (B), $\mathrm{N_3P_3Cl_3F_3}$ (C), $\mathrm{N_3P_3Cl_2F_4}$ (D), $\mathrm{N_3P_3ClF_5}$ (E). Compositions among these which can give isomeric products are

(d)E, A and B

(a)A, B and C

(b)B, C and D

(c)C, D and E

Answer

Answer (as printed): C

Explanation

$\mathrm{N_3P_3Cl_3F}$ (A) = only 1 isomer. $\mathrm{N_3P_3Cl_4F}$ (B) = 3 isomers. $\mathrm{N_3P_3Cl_3F_3}$ (C) = 3 isomers. $\mathrm{N_3P_3Cl_2F_4}$ (D) = 3 isomers. $\mathrm{N_3P_3ClF_5}$ (E) = 1 isomer.

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