Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Exam: CSIR-NET 2016 · Marks: 2 · Difficulty: Medium
The compound which dissolves in $\mathrm{POCl_3}$ to give a solution with highest chloride ion concentration ,is -
\[ \mathrm{POCl_6^{-}} + \mathrm{Cl^{-}} \rightarrow \mathrm{POCl_4^{-}} \quad (\mathrm{Cl^{-}}\text{ concentration is not enhanced}) \]
(ii) $\mathrm{KCl}$: $\mathrm{KCl} \rightarrow \mathrm{K^{+}} + \mathrm{Cl^{-}}$. The $\mathrm{Cl^{-}}$ ion produced in this reaction increases the concentration of $\mathrm{Cl^{-}}$, and it is not consumed by $\mathrm{POCl_3}$.(iii) $\mathrm{FeCl_3} + \mathrm{OPCl_3} \rightarrow \mathrm{POCl_2^{+}} + \mathrm{FeCl_4^{-}}$(iv) $\mathrm{SbCl_6} + \mathrm{OPCl_3} \rightarrow \mathrm{POCl_2^{+}} + \mathrm{SbCl_6^{-}}$