The oxidative addition and reductive elimination steps are favoured by
(a)Electron rich metal centres
(b)Electron deficient metal centers
(c)Electron deficient and electron rich metal centers respectively.
(d)Electron rich and electron deficient metal centers respectively
Answer
Answer (as printed): D
Explanation
Oxidation of the metal is easier for electron-rich systems, so electron-rich metals undergo oxidative addition, and as reduction is easier for electron-deficient metal, it undergoes reductive elimination.