In hydrofomylation reaction using $\mathrm{[Rh(PPh_3)_2(CO)(H)]}$ as the catalyst, addition of excess $\mathrm{PPh_3}$, would
(a)increase the rate of reaction
(b)decrease the rate of reaction.
(c)not influence of the rate of reaction
(d)stop the reaction.
Answer
Answer (as printed): B
Explanation
An 18-electron species; in excess $\mathrm{PPh_3}$ it becomes a 20-electron species, but the active catalyst is a 16-electron species. So, in the presence of excess $\mathrm{PPh_3}$, the rate of hydroformylation will decrease.