In trigonal prismatic ligand field, the most stabilized d orbital is
(a)$\mathrm{d_z}^{2}$
(b)$\mathrm{d_{xy}}$
(c)$\mathrm{d_{xz}}$
(d)$\mathrm{d_{yz}}$
Answer
Answer (as printed): B
Explanation
In trigonal prismatic ligand field, energy of 'd' orbital is $d_{yz}=d_{xz} > d_{z^2} > d_{x^2-y^2}=d_{xy}$Hence, the most stabilized 'd' orbital is $d_{xy}$