In the complex $[\mathrm{Pd(L\text{-}L)(Me)(Ph)}]$, the bisphosphine (L-L) that does not allow reductive elimination of PhMe is
(a)
(b)
(d)
Answer
Answer (as printed): D
Explanation
According to reductive elimination reaction mechanism cis-complex can give the product but trans-complex is not suitable for reaction and does not give reductive elimination product.Since, ligand given in option (d) forms a trans-complex with $\mathrm{Pd^{II}}$ due to the presence of flexible methylene ($\mathrm{-CH_2-}$) groups.Therefore, reductive elimination not occurred.Actually formed but does not give reactionThis can give reaction but not formed