Hydroformylation of 1-propene with $\left[\mathrm{HRh}(\mathrm{CO}) \mathrm{L}_{\mathrm{2}}\right]$ leads to linear and branched formylated products. The linear hydroformylated product is formed with highest selectivity when 'L' in the rhodium complex is
Answer
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Explanation
Bite angle $85^{\circ}$, $91^{\circ}$, $>120^{\circ}$, $96^{\circ}$The linear and branched formylated product depends upon natural bite angle of bisphosphines.As the natural bite angle increases selectivity for linear product increases.