The following table lists the reaction/conversion catalyzed by metalloenzymes. · ABC26IN0312

Subject: Inorganic Chemistry · Chapter: Bioinorganic Chemistry · Topic: Bioinorganic – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

The following table lists the reaction/conversion catalyzed by metalloenzymes.
Reaction/conversionMetalloenzyme
P$\mathrm{R-H+O_2+2H^{+}+2e^{-} \rightarrow R-OH+H_2O}$ICoenzyme $\mathrm{B_{12}}$
Q$\mathrm{O_2+4e^{-}+8H^{+} \rightarrow 2H_2O+4H^{+}}$IICytochrome P-450
R$\mathrm{2H_2O_2 \rightarrow2H_2O+O_1}$IIICytochrome c oxidase
S$\mathrm{NH_2-CH_2-CO_2H \rightarrow NH_2-CH(CH_2OH)-CO_2H}$IVCatalase
(a)P-I; Q-IV; R-III; S-II
(b)P-II; Q-III; R-IV; S-I
(c)P-IV; Q-III; R-II; S-I
(d)P-II; Q-I; R-III; S-IV
Answer
Answer: B ✓ checked by 4AB · confidence high

The printed key (c) is wrong: it pairs P with catalase and R with P-450. P-450 is the R–H hydroxylase and catalase disproportionates H₂O₂, which gives (b).

Explanation
P (R–H + O₂ + 2H⁺ + 2e⁻ → R–OH + H₂O, monooxygenation of a C–H bond) – cytochrome P-450 (II). Q (four-electron reduction of O₂ to water, coupled to proton pumping) – cytochrome c oxidase (III). R (disproportionation 2H₂O₂ → 2H₂O + O₂; the table's 'O₁' is a misprint for O₂) – catalase (IV). S (glycine → serine) is the remaining pair, coenzyme B₁₂ (I). Only option (b) has P-II, Q-III, R-IV, S-I. The printed key (c) would make catalase the hydroxylase and P-450 the peroxide-disproportionation enzyme, which is wrong. Answer: (b).

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