The bond angle in PBr₃ is 101°. The percent 's' character of the central atom is ____. · ABC26IN0574
Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Exam: JAM 2005-2022 · Marks: 2 · Difficulty: Medium
The bond angle in $\mathrm{PBr}_{3}$ is $101^{\circ}$. The percent 's' character of the central atom is ____.
Answer
Answer (as printed): 16.02
The options are missing from the source scan for this question, so there is nothing here for this letter to point at. The letter is what the book printed.
Explanation
Answer: 16.02 % — For equivalent hybrids cos θ = −α/(1 − α): cos 101° = −0.1908 → α = 0.1908/1.1908 = 0.1602, i.e. 16.02 % s-character.