ABC26PH0047 · Chemical Kinetics

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Exam: CSIR-NET DEC 2019 · Marks: 2 · Difficulty: Hard

The oxidation of $\mathrm{NO}$ to $\mathrm{NO_2}$ occurs via the mechanism given below.
\[ \begin{array}{l} 2\,\mathrm{NO} \underset{k_{-1}}{\overset{k_1}{\rightleftharpoons}} \mathrm{N_2O_2} \\ \mathrm{N_2O_2+O_2} \xrightarrow{k_2} 2\,\mathrm{NO_2} \end{array} \]
$\dfrac{d[\mathrm{NO_2}]}{dt}$ in the presence of large excess of $\mathrm{O_2}$ can be written as
(a)$2k_1(\mathrm{NO})^{2}$
(b)$2k_1k_2(\mathrm{NO})^{2}(\mathrm{O_2})$
(c)$\dfrac{k_1}{k_2}(\mathrm{NO})^{2}$
(d)$2k_2(\mathrm{NO})^{2}$
Answer
Answer (as printed): A
Explanation
No explanation was printed for this question.

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