ABC26PH0054 · Electrochemistry
Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Exam: CSIR-NET DEC 2012 · Marks: 2 · Difficulty: Easy
The Daniel cell is
(a)$\mathrm{Pt}_{\mathrm{I}}(\mathrm{s})|\mathrm{Zn}(\mathrm{s})| \mathrm{Zn}^{2+}(\mathrm{aq}) \| \mathrm{Cu}^{2+}(\mathrm{aq})|\mathrm{Cu}(\mathrm{s})| \mathrm{Pt}_{\mathrm{II}}$
(b)$\mathrm{Pt}_{\mathrm{I}}(\mathrm{s})|\mathrm{Zn}(\mathrm{s})| \mathrm{Zn}^{2+}(\mathrm{aq}) \| \mathrm{Ag}^{2+}(\mathrm{aq})|\mathrm{Ag}(\mathrm{s})| \mathrm{Pt}_{\mathrm{II}}$
(c)$\mathrm{Pt}_{\mathrm{I}}(\mathrm{s})|\mathrm{Fe}(\mathrm{s})| \mathrm{Fe}^{2+}(\mathrm{aq}) \| \mathrm{Cu}^{2+}(\mathrm{aq})|\mathrm{Cu}(\mathrm{s})| \mathrm{Pt}_{\mathrm{II}}$
(d)$\mathrm{Pt}_{\mathrm{I}}(\mathrm{s})\left|\mathrm{H}_{2}(\mathrm{s})\right| \mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \| \mathrm{Cu}^{2+}(\mathrm{aq})|\mathrm{Cu}(\mathrm{s})| \mathrm{Pt}_{\mathrm{II}}$
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.
Explanation
No explanation was printed for this question.
Open in whiteboard · Browse this chapter in the app