The equilibrium constant for an electrochemical reaction, 2\,Fe3++Sn2+ 2\,Fe2++Sn4+ is [Eo_Fe3+/Fe2+=0.75\,V,\ Eo_Sn4+/Sn2+=0.15\,V;\ 2.303RT/F=0.06\,V ]

ABC26PH0056 · Electrochemistry

Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Exam: CSIR-NET DEC 2012 · Marks: 2 · Difficulty: Medium

The equilibrium constant for an electrochemical reaction,

\[ 2\,\mathrm{Fe}^{3+}+\mathrm{Sn}^{2+} \rightleftharpoons 2\,\mathrm{Fe}^{2+}+\mathrm{Sn}^{4+} \]

is $\left[E^{o}_{\mathrm{Fe^{3+}/Fe^{2+}}}=0.75\,V,\ E^{o}_{\mathrm{Sn^{4+}/Sn^{2+}}}=0.15\,V;\ \dfrac{2.303RT}{F}=0.06\,V\right]$

(a)$10^{10}$

(b)$10^{20}$

(c)$10^{30}$

(d)$10^{40}$

Answer

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Explanation

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