The $\mathrm{C}=\mathrm{O}$ bond length is 120 pm in $\mathrm{CO}_{2}$. The moment of inertia of $\mathrm{CO}_{2}$ would be close to (masses of C and O are $1.9 \times 10^{-27} \mathrm{kg}$ and $2.5 \times 10^{-27} \mathrm{kg}$, respectively)
(a)$1.8\times10^{-45}\,\mathrm{kg\,m^{2}}$
(b)$3.6\times10^{-45}\,\mathrm{kg\,m^{2}}$
(c)$5.4\times10^{-45}\,\mathrm{kg\,m^{2}}$
(d)$7.2\times10^{-45}\,\mathrm{kg\,m^{2}}$
Answer
Answer (as printed): D
Explanation
The moment of inertia of $\mathrm{CO_2}$.
\[ I = 2m_O R^{2} \]
\[ I = 2\times2.5\times10^{-27}\,\mathrm{kg}\times(120\,\mathrm{pm})^{2} \]
\[ I = 2\times2.5\times10^{-27}\,\mathrm{kg}\times(120\times10^{-12}\,\mathrm{m})^{2} \]
\[ I = 5\times14400\times10^{-51}\,\mathrm{kg\,m^{2}} \]