Two different non-zero operators A and B (A ≠ B) satisfy the relation (A+B)(A-B) = A² - B² · ABC26PH0162

Subject: Physical Chemistry · Chapter: Quantum Chemistry · Topic: Postulates Operators · Exam: CSIR NET 2015 · Marks: 2 · Difficulty: Medium

Two different non-zero operators $\hat{A}$ and $\hat{B}$ $(\hat{A} \neq \hat{B})$ satisfy the relation $(\hat{A}+\hat{B})(\hat{A}-\hat{B}) = \hat{A}^2 - \hat{B}^2$

(a)$\hat{A}\hat{B} = \hat{A}^2$ and $\hat{B}\hat{A} = \hat{B}^2$

(b)$\hat{A}\hat{B} + \hat{B}\hat{A} = 0$

(c)$\hat{A}$ and $\hat{B}$ are arbitrary

(d)$\hat{A}\hat{B} - \hat{B}\hat{A} = 0$

Answer

Answer (as printed): D

Explanation

No explanation was printed for this question.

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