For a hermitian operator A, which does NOT commute with the Hamiltonian H, let $\psi_1$ be an eigenfunction of A and $\psi_2$ be an eigenfunction of H. The correct statement regarding the average value of the commutator of A with H ([A,H]) is
(a)both $\langle\psi_1|[A,H]|\psi_1\rangle$ and $\langle\psi_2|[A,H]|\psi_2\rangle$ are non-zero
(b)only $\langle\psi_1|[A,H]|\psi_1\rangle$ is zero, but $\langle\psi_2|[A,H]|\psi_2\rangle$ is non-zero
(c)only $\langle\psi_2|[A,H]|\psi_2\rangle$ is zero, but $\langle\psi_1|[A,H]|\psi_1\rangle$ is non-zero
(d)both $\langle\psi_1|[A,H]|\psi_1\rangle$ and $\langle\psi_2|[A,H]|\psi_2\rangle$ are zero