ABC26PH0188 · Solid State Chemistry

Subject: Physical Chemistry · Chapter: Solid State Chemistry · Topic: Crystal Systems Lattices · Exam: CSIR-NET JUNE 2014 · Marks: 2 · Difficulty: Medium

The interplanar spacing of (110) planes in a cubic unit cell with lattice parameter $a=4.242$ Å is

(a)$3 \AA$

(b)$6 \AA$

(c)$7.35 \AA$

(d)$2.45 \AA$

Answer

Answer (as printed): A

Explanation

$d_{hkl}=\dfrac{a}{\sqrt{h^{2}+k^{2}+l^{2}}}$, $d_{110}=3\,\text{Å}$.

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